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Home Jack Sarfatti's Blog Blog (Full Text Display) it's physically obvious why our future dark energy horizon is the Wheeler-Feynman total absorber.

Apr
24

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This is why I like the tetrad formalism because then the electro-gravitic coupling is simply that between two spin 1 vector gauge fields one for internal U1 the other for space-time de Sitter group with Einstein's cosmological constant positive not equal to zero. The coupling is simply given by the Einstein equivalence principle. Very neat and pretty.

Then from Penrose each tetrad is an Einstein-Podolsky-Rosen quantum entangled state of pairs of spinor QUBITS! There are two kinds of QUBITS the advanced destiny QUBITs with support on the past light cone, and the retarded history QUBITS with support on the future light cone all set up for the Wheeler-Feynman POV with the future boundary dark energy event horizon in effect the Wheeler-Feynman total absorber only when / > 0. Since we are retrocausal hologram images from our future boundary - the 2D Quantum Field Theory on our event horizon is the Omega Source of the quantum gravity fluctuations making inelastic collisions with real photons - the mean values (Ehrenfest's theorem) giving the classical cosmological stretch of the photon wavelength with the FRW scale factor a(t).

I meant dark energy density / accelerating space is the absorber! If the cosmological constant / is zero my picture might not work.

The acceleration c^2/^1/2 compared to / = 0 case (first order perturbation theory) means accelerating space's geometrodynamic field is like a black body cosmological fluid (Unruh effect).

On Apr 23, 2010, at 1:24 AM, JACK SARFATTI wrote:

Think of Ehrenfest's theorem. The photon is represented by a probability wave. What we have is a coupling between the EM and time-changing gravity cosmological field. In the usual collapse picture (for now) a random collapse happens where the photon is absorbed by a quantum fluctuation in the dynamic gravity field and then re-emitted at a lower frequency - in such a way that the statistical mean obeys the classical redshift picture. After a finite distance at the de Sitter horizon there is no photon left at all (infinite stretch of wavelength in finite distance) - so in each individual photon case Cramer's return waves happen randomly in each inelastic collision with the time-varying gravity field. Time-varying gravity fields can emit and absorb particles. I think my intuitive picture can be made to work even in the absence of electrons and ions - expanding space itself is an absorber.

On Apr 23, 2010, at 12:12 AM, james f woodward wrote:

"Well, you know that I think the WFHNC action at a distance picture is the correct one. And that accelerating expansion solves the cut off problem. So, I must admit that I am sympathetic to your proposal. But you must admit that it's a stretch to call stringing out photons absorption that triggers an advanced response. :-)"

On Thu, 22 Apr 2010 02:33:10 -0700 JACK SARFATTI <sarfatti@pacbell.net>

writes:

When a real photon is absorbed it disappears - in effect w = k = 0 after absorption. OK we shine a light into the sky - that light will shift down to w = k = 0 in a finite distance from us because space has stretched in an accelerating way. The gravity field itself adiabatically absorbs the photon energy! We don't need no damn atoms any more than we need badges! ;-)

Hence it will trigger a return Cramer wave back to us in time with compensating blue shift. This is completely obvious to me at least.