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Tag » Richard P. Feynman
  1. Not all three statements are consistent it is claimed.
  2. 1) Hawking radiation is in a pure state.
  3. 2) The information carried by the radiation is emitted from the region near the horizon, with low energy effective field theory valid beyond some microscopic distance from the horizon.
  4. 3) The infalling observer encounters nothing unusual at the horizon.
 
 
Well 1) cannot be true since if Hawking radiation is black body it is not in a pure state it is a mixed state with a reduced density matrix that is not an idempotent projection operator.
 
 
So what is all the fuss about? ;-)
 
Throw away 1) and keep 2) and 3)?
 
Furthermore, there is no reason to go hog wild that the universe obeys unitarity at all levels of organization. Why should probability be conserved in the first place? Life does not seem to conserve probabilities. When Feynman gave an early lecture on his Lagrangian formulation of quantum theory Dirac was there with Einstein and Dirac asked Feynman if his theory was “unitary.” Feynman said he had no idea of what Dirac even meant at that time. Valentini has an extended quantum theory that is definitely not unitary for example. Feynman also asked why observables have to be Hermitian operators. Hermitian operators generate unitary transformations.
 
 
Unitarity is in Hilbert qubit pilot wave space what orthogonality is in the spacetime continuum. There is nothing sacred and absolute in either. There is no compelling reason to say that inner products of quantum states are invariant under time evolution. It works in a limited range of experiments - scattering experiments - very primitive smashing of things together - brute force not very subtle.
 
 
The S-MATRIX is a crude tool that has been elevated into The Golden Calf by the Priests of Orthodox Physics.
 
 
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On Jun 30, 2014, at 11:45 AM, Paul Zielinski <iksnileiz@gmail.com> wrote:

"In any case, the SEP is really just a conjecture. Also there is something fundamentally wrong with a theory in which the existence of radiation is frame dependent. Surely it should at least be possible to settle this question empirically?"

No, look at the Unruh effect.
Virtual photons in inertial frames are real photons in coincident non-inertial frames. This is the origin of the firewall debate on black holes.There is a creative tension between equivalence principle and charges emitting photons
If a charge sits at surface of Earth it has a constant proper acceleration in a static LNIF. Feynman would say no problem - constant acceleration does not cause real photon emission - to who? others ask.
 
If you accumulate a lot of unbalanced electric charge and just let it sit on a lab table do you expect it to radiate real photons? Where is the energy coming from?
 
In Wheeler-Feynman-Cramer - the emission of real photons is a transaction between emitter and absorber with advanced confirmation. So now there are four cases emitter rest frame in LIF or LNIF, absorber rest frame in LIF' or LNIF'
 
We do not expect any real photon emission in the geodesic LIF <—> geodesic LIF' case. What about the other three?
 
 

 

On 6/29/2014 9:39 PM, Jack Sarfatti wrote:
Still up in the air

Sent from my iPad

On Jun 29, 2014, at 7:00 PM, Paul Zielinski <iksnileiz@gmail.com> wrote:

Here is a more in depth discussion of the problem by R. Scalise, which raises doubts about
Feynman's answer based on more recent work:

http://www.physics.smu.edu/scalise/P7312fa12/ChoiceCutsCh52.pdf

On 6/29/2014 6:47 PM, Paul Zielinski wrote:
Informative discussion on this topic by Kevin Brown available here:

http://www.mathpages.com/home/kmath528/kmath528.htm

On 6/29/2014 6:37 PM, Jack Sarfatti wrote:
1) an electric charge on a time like geodesic should not radiate transverse photons.

2) Feynman showed that a charge in uniform acceleration does not radiate.

This is obvious since radiation reaction depends on the jerk covariant derivative of

D^2V^u/ds^2

Note that this is complicated in LNIFs.

Sent from my iPad