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On Jun 30, 2014, at 11:45 AM, Paul Zielinski <iksnileiz@gmail.com> wrote:

"In any case, the SEP is really just a conjecture. Also there is something fundamentally wrong with a theory in which the existence of radiation is frame dependent. Surely it should at least be possible to settle this question empirically?"

No, look at the Unruh effect.
Virtual photons in inertial frames are real photons in coincident non-inertial frames. This is the origin of the firewall debate on black holes.There is a creative tension between equivalence principle and charges emitting photons
If a charge sits at surface of Earth it has a constant proper acceleration in a static LNIF. Feynman would say no problem - constant acceleration does not cause real photon emission - to who? others ask.
 
If you accumulate a lot of unbalanced electric charge and just let it sit on a lab table do you expect it to radiate real photons? Where is the energy coming from?
 
In Wheeler-Feynman-Cramer - the emission of real photons is a transaction between emitter and absorber with advanced confirmation. So now there are four cases emitter rest frame in LIF or LNIF, absorber rest frame in LIF' or LNIF'
 
We do not expect any real photon emission in the geodesic LIF <—> geodesic LIF' case. What about the other three?
 
 

 

On 6/29/2014 9:39 PM, Jack Sarfatti wrote:
Still up in the air

Sent from my iPad

On Jun 29, 2014, at 7:00 PM, Paul Zielinski <iksnileiz@gmail.com> wrote:

Here is a more in depth discussion of the problem by R. Scalise, which raises doubts about
Feynman's answer based on more recent work:

http://www.physics.smu.edu/scalise/P7312fa12/ChoiceCutsCh52.pdf

On 6/29/2014 6:47 PM, Paul Zielinski wrote:
Informative discussion on this topic by Kevin Brown available here:

http://www.mathpages.com/home/kmath528/kmath528.htm

On 6/29/2014 6:37 PM, Jack Sarfatti wrote:
1) an electric charge on a time like geodesic should not radiate transverse photons.

2) Feynman showed that a charge in uniform acceleration does not radiate.

This is obvious since radiation reaction depends on the jerk covariant derivative of

D^2V^u/ds^2

Note that this is complicated in LNIFs.

Sent from my iPad

PS
Everyone, except perhaps Jim, agrees that a retarded EM OFFER wave from Alice falling on a hovering detector Bob very close to any future horizon of area-entropy A either black hole or de Sitter or Rindler will blue shift. According to Jim the return advanced CONFIRMATION wave to Alice will blue shift even more! Hence, a HANDSHAKE is impossible due to the enormous frequency mismatch in Jim's way of thinking.

i.e.

fret(Alice) ---> fret(Bob) ~  (A^1/4/Lp^1/2)fret(Alice) 
According to Jim,
fadv(Alice) = (A^1/4/Lp^1/2)fret(Bob) = (A^1/2/Lp)fret(Alice) 
fadv(Alice) >> fret(Alice) 
violates TI


On Jun 6, 2013, at 12:52 PM, JackSarfatti <JackSarfatti@comcast.net> wrote:

Jim's scheme violates TI because Jim if he worked out his idea in detail would have advanced offer wave at a higher frequency than the retarded confirmation wave at the PAST absorber in the retrocausal case.

Sent from my iPhone

On Jun 6, 2013, at 12:35 PM, Ruth Kastner  wrote:

"The only reason I replied was because of your claim that Jim's model 'violates Cramer's TI' -- to point out that your debate with Jim has no bearing on TI.  Nor does my model obscure any important conceptual insights.

Best wishes"
RK

 

http://www.academia.edu/36632/Debate_on_cosmology_Sarfatti_vs_Woodward_Part_1

Jim also confuses the Hubble sphere where expansion speed is that of light with the cosmic horizons.

if you use static coordinates

gtt = 1 - r^2/A

1 + z = [gtt(receiver)/gtt(source)]^1/2

use  r ~ A^1/2 - Lp  in gtt(source)  and r = 0 for gtt(receiver)

for advanced offer wave in the Cramer transaction

result is (first order Taylor series)

1 + z ~ (1/(Lp/A^1/2)^1/2) = (A^1/2/Lp)^1/2

---> infinity as Lp ---> 0

My argument in co-moving Friedmann coordinates below is consistent with the in static coordinates above.

As above
So below ;-)

Indeed Tamara Davis in her PhD says what I say about the change of distance to our past and future horizons It's obvious from her diagram (Fig 1.1)

We recede from our past particle horizon, we approach our future dark energy de Sitter horizon.

1) In a Cramer transaction a retarded offer wave to us from near our past horizon is redshifted.

An advanced confirmation wave from us to near our past particle horizon is blue shifted.


Our relative space is effectively expanding forward in time in this transaction with our past horizon.

2) In a Cramer transaction an advanced offer wave to use from our future horizon is redshifted.

A retarded confirmation wave from us to it is blue shifted.

Our relative space is effectively contracting forward in time in this transaction with our future horizon.

Therefore, it is effectively expanding backwards in time for a back from the future advanced wave to us.

Advanced Wheeler-Feynman Hawking black body radiation of peak energy hc/Lp is then redshifted down to hc/(LpA^1/2)^1/2 at our detectors.

From Stefan-Boltzmann T^4 law this gives energy density hc/Lp^2A, which happens to agree with the actual dark energy density accelerating out causal diamond observable patch of the multiverse.

A = area of our future horizon at intersection with our future light cone.




Jack Sarfatti proper acceleration in a static coordinate metric

ds^2 = gttdt^2 - grrdr^2 - r^2(spherical coordinate metric)

is

g(r) ~ gtt^-1/2d(g00/dr)

the two metrics of interest are

gtt = 1 - A^1/2/r black hole of area entropy A

we at r ---> infinity outside black hole

gtt = 1 - r'^2/A de Sitter horizon

we at r' = 0

inside cosmological horizon

use

1 + z = femit/fobserve f = frequency

1 + z = [gtt(observe)gtt(emit)]^1/2

http://en.wikipedia.org/wiki/Redshift

Quantum gravity says horizons gtt = 0 are really Lp thick.

so for both metrics above using

r = A^1/2 + Lp for black hole

&

r' = A^1/2 - Lp

get same factors (Lp/A^1/2)^1/2 redshift of radiation emitted from A

(A^1/2/Lp)^1/2 blue shift of radiation falling into A.

Now the Hawking black hole radiation temperature at A is

T ~ h(A^1/2/Lp)c^2/cA^1/2kB ~ hc/kB(LpA^1/2)^1/2

and this redshifts down to hc/A^1/2kB ~ Newtonian horizon surface gravity just as Hawking says.

In contrast, for the new quantum gravity radial oscillations of the thickness of the horizon

T' ~ hc/LpkB

which redshifts down to us to T' ~ hc/kB(LpA^1/2)^1/2

by Stephan Boltzman T^4 law

this gives hc/Lp^2A

both for anomalous w = +1/3 radiation from black holes whose horizon is not observer dependent

& also dark energy density from future horizon which looks like w = -1 virtual photon vacuum energy peaked at c/(LpA^1/2)^1/2 frequency whose horizon is observer dependent.

We need to use John Cramer's TI here.

en.wikipedia.orgIn physics (especially astrophysics), redshift happens when light seen coming from an object that is moving away is proportionally increased in wavelength, or shifted to the red end of the spectrum. More generally, when an observer detects electromagnetic radiation outside the visible spectrum, "red...

Notes on my Star Gate book
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  • Jack Sarfatti The equation in question is (in index-free short hand)

    DU/ds = dU/ds + {LC}UU

    This is a tensor equation- a geometric object, and the choices of local coordinate patches of differential geometry are irrelevant.

    We are interested in this book in the heuristic physical meaning of the equations not in the excess baggage of formalism that only obscures the essential physics leading many physicists astray into purely mathematical dead ends perhaps important to pure mathematics but not to physics. The Cornell philosophy of Hans Bethe, Ed Salpeter, Phil Morrison, Tommy Gold and Richard Feynman himself was to get the most physics with the least possible mathematics. This is in accord with Einstein's remark that any intelligent fool can make the subject more complicated than it need be. Indeed, this is the trend we see in modern theoretical physics today.

    DU/ds is what accelerometers measure locally on the test particle being observed.

    {LC}UU is what accelerometers measure locally on the detector observer of the test particle.

    dU/ds is the apparent or kinematical 4-acceleration of the test particle relative to the detector.

    The test particle and the detector are nearly coincident, i.e. their actual space-time separation must be small compared to the local radii of curvature of 4D spacetime for the equation not to break down. For example on Earth surface that curvature radius is about 10^13 cm, so this is not a problem for local experiments.

    The Levi Civita connection {LC} in Einstein's GR physically describes the fictitious inertial pseudo forces that appear to act on test particles. These inertial forces are caused by real forces on the local noninertial frames lnifs measuring the motion of the test particle.

    Newton's 2nd Law is for rest mass m constant

    F = mDV/ds = real 4-force

    V = 4-velocity of test particle

    ds = proper time differential

    DV/ds = dV/ds - {LC}VV = proper 4-acceleration. it is a gct group tensor

    In a local inertial frame lif {LC} = 0

    This is Einstein's equivalence principle

    In a local non inertial frame lnif

    {LC} =/= 0

    - m{LC}VV = all the inertial fictitious pseudo forces that seem to act on the test particle from the POV of the properly accelerating lnif detector observer, but don't.

    Note the g00 in the denominator that is zero at horizons.

    Note also that the quantum Unruh effect in which vacuum zero point virtual photons are transformed into real black body radiation photons is proportional to the local tensor proper acceleration DU/ds of the detector accelerometer.