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I compute that black holes have much shorter evaporation times than Hawking et-al first computed. They computed surface vibrations and neglected thickness vibrations due to geometrodynamical field zero point vacuum fluctuations.

On Apr 9, 2014, at 5:02 PM, Paul Zielinski <iksnileiz@gmail.com> wrote:

On 4/9/2014 4:42 PM, JACK SARFATTI wrote:
According to Einstein’s classical geometrodynamics, our future dark energy generated cosmological horizon is as real, as actualized as the cosmic blackbody radiation we measure in WMAP, Planck etc.

But doesn't its location depend on the position of the observer? How "real" is that?
Irrelevant, red herring.
Alice has to be very far away from Bob for their respective de Sitter horizons not to have enormous overlap.
We all have same future horizon here on Earth to incredible accuracy.

I assume by "dark energy generated" you simply mean that the FRWL metric expansion is due to /, and
/ registers the presence of dark energy.
What else? Obviously.

We have actually measured advanced back-from-the-future Hawking radiation from our future horizon. It’s the anti-gravitating dark energy Einstein cosmological “constant” / accelerating the expansion of space.

OK so the recession of our future horizon produces Hawking-like radiation due to the acceleration of our frame of reference
wrt the horizon?
No, static LNIF hovering observers have huge proper accelerations at Lp from the horizon with redshifted Unruh temperature T at us
kBT ~ hc/(A^1/2Lp^1/2)^1/2
use black body law
energy density ~ T^4
to get hc/ALp^2
The static future metric is to good approximation
g00 = (1 - r^2/A)
we are at r = 0
future horizon is g00 = 0
imagine a static LNIF hovering observer at r = A^1/2 - Lp
his proper radial acceleration hovering within a Planck scale of the horizon is
g(r) ~ c^2(1 - r^2/A)^-1/2 (A^1/2 - Lp)/A
= c^2(1 - (A^1/2 - Lp)^2/A)^-1/2(A^1/2 - Lp)/A
= c^2(1 - (1 - 2 Lp/A^1/2 + Lp^2/A )^-1/2(A^-1/2 - Lp/A)
= c^2(2Lp/A^1/2 - Lp^2/A )^-1/2(A^-1/2 - Lp/A)
~ c^2(2Lp^-1/2/A^-1/4 )A^-1/2(1 - Lp/A^1/2)
~ c^2(A^1/4/Lp^1/2)A^-1/2 ~ c^2/(Lp^1/2A^1/4)
f(emit) = c/(Lp^1/2A^1/4)
1 + z = (1 - (A^1’2 - Lp)^2/A)^-1/2 = (A^1/4/Lp^1/2) 
f(obs) = f(emit)/(1 + z) = Lp^1/2/A^1/4c/(Lp^1/2A^1/4) = c/A^1/2
OK this is the standard low energy Hawking radiation formula from surface horizon modes
However, there is a second high energy quantum thickness radial mode
f'(emit) ~ c/Lp
f’(obs) = (Lp^1/2/A^1/4)c/Lp = c/(Lp^1/2A^1/4)
This advanced Wheeler-Feynman de Sitter blackbody radiation is probably gravity waves not electromagnetic waves.

You seem to be drawing a direct physical analogy between cosmological horizons and black hole horizons.
Hawking Gibbins did so in 1977 i sent his paper several times.
This requires the anti-Feynman contour for advanced radiation in quantum field theory.
i.e. mirror image of this
so that w = + 1/3 blackbody advanced radiation anti-gravitates
It’s energy density is ~ hc/Lp^2A
A = area of future horizon where the future light cone of the detector intersects it.



On Apr 12, 2013, at 12:22 AM, Ruth Kastner <rekastner@hotmail.com> wrote:

I agree that 'no mysticism' need be involved in explaining results of measurements, and that (to put it charitably)  Wheeler's contributions to physics were far greater than his contributions to philosophy of physics.

 I address these foundational matters in my new book on PTI. Bohm's theory may seem to provide a handy way to solve the measurement problem, however it encounters some serious challenges at the relativistic level.  It has also been argued by Harvey Brown and David Wallace (2005) that even at the nonrelativistic level there are problems with the idea that a Bohmian corpuscle can give you a measurement result (ref. on request).

please send reference

On the other hand  TI (extended in terms of PTI) finds its strongest expression at the relativistic level, in that one has to take absorption into account in the relativistic domain in any case, and absorption is the key overlooked aspect according to TI. In fact I argue that the measurement problem remains unsolved in the competing 'mainstream' nonrelativistic interpretations because they neglect the creation and annihilation of quanta. Emission is action by creation operators, and absorption is action by annihilation operators. You can get a definitive end to the measurement process by taking absorption (aka annihilation) into account. This happens way before the macroscopic level (see http://arxiv.org/abs/1204.5227, section 5) so that you don't get the usual infinite regress of entanglement of macroscopic objects which is the measurement problem.


I agree about the importance of including both creation and destruction in a time loop, but I don't see off-hand that is a problem for Bohm's theory.

Indeed, in my debate with Jim Woodward on dark energy density hc/Lp^2A as redshifted advanced Wheeler-Feynman Hawking radiation from our detector dependent future de Sitter horizon where the Hawking radiation density is hc/Lp^4 - the TI loop in time means that we must use the static LNIF representation of the metric for the virtual electron-positron pairs stuck at r = A^1/2 - Lp relative to the detector at r = 0 where

gtt = 1 - r^2/A

giving 1 + zstaticLNIF ~ (A^1/2/Lp)^1/2 = femit/fdetect

not the usual FRW metric where gtt = 1 and there is no horizon - that works for co-moving absorbers that will see the effect of expanding space for retarded radiation from us &  1 + zcomovingLIF = anow/athen

The static LNIF redshift factor for advanced radiation source frequency c/Lp from the future horizon back to our past detector is ~ (Lp/A^1/2)^1/2.

Even for retarded black body radiation reaching us from a past black hole horizon with Hawking's original redshifted peak frequency c/A^1/2, there should be a second peak signal at c/(LpA^1/2)^1/2 from radial oscillations of the horizon. Hawking's signal is from surface mode vibrations of the horizon.

New idea hit me last night 3AM London time on jet lag.
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  • Cesar Estrada likes this.
  • Jack Sarfatti Hawking's low freq radiation are analogous to Goldstone modes, my new high freq horizon signal is like a Higgs signal.
  • Jack Sarfatti On jet-lag in London from SFO

    Hawking radiation peak frequency is c/A^1/2

    A = area entropy of 2D horizon gtt = 0.

    Think of horizon as spherical membrane of thickness Lp.

    So c/A^1/2 are the theta, phi phase waves in an effective order parameter potential V(r, theta, phi).

    As A ---> infinity the frequency ---> 0 - massless Goldstone mode.

    However, the Higgs mode I predict is in the radial vibrations peak frequency c/Lp gets red shifted by (Lp/A^1/2)^1/2 < 1 at the detector to peak frequency

    c/(LpA^1/2)^1/2 > c/A^1/2

    In limit A ---> infinity both modes are gapless, but as soon as A is finite the Higgsian type mode splits off a higher frequency branch.

    Not sure how far this analogy goes, but I want to record it just in case.
  1. I predict a new high energy signal from the event horizons of black holes in addition to the low energy signal predicted by Stephen Hawking.
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    • Jack Sarfatti Thorizon ~ hc/rskB

      R. Buosso Adventures in de Sitter Space

      The proper acceleration of virtual particles stuck in the horizon of Planck length thickness Lp and area-entropy A is

      g ~ gtt^-1/2dgtt/dr

      However, the retarded radiation gravity redshift factor from a past black hole is calculated from

      Gravitational redshift any stationary spacetime (e.g. the Schwarzschild geometry)
      (for the Schwarzschild geometry,

      The receiver is always at r ---> infinity, therefore, gtt(receiver) = 1


      fobsv/femit = (1 + z)^-1 ---> gtt(source)^1/2 = (1 - 2GM/c^2rsource)^1/2

      Therefore, the gtt^1/2 factors cancel in numerator and denominator and the resulting Hawking-Unruh-Bekenstein (HRB) temperature (peak frequency) of the blackbody signal is simply proportional to the Newtonian event horizon surface gravity acceleration c^2/rs (the IR

      rs ~ GM/c^2

      Computing this in more detail, we must use for the virtual particle radiators stuck to the gtt = 0 horizon source

      rsource ~ rs + Lp

      Lp/rs << 1

      gtt^1/2 ~ [1 -rs/(rs + Lp)]^1/2 ~ [1 - 1/(1 + Lp/rs)]^1/2

      ~ (Lp/rs)^1/2 << 1 = gravity red shift factor

      Now, what Hawking et-al predict are the LOW ENERGY IR surface eigen-modes from ripples in the event horizon area.

      There, should also be HIGH ENERGY UV radial eigen-modes of fundamental frequency c/Lp from the horizon.

      These also get redshifted down to our detectors to peak signal frequency c/(Lprs)^1/2

      i.e. wavelength = geometric mean of Planck scale with horizon scale.

      When we apply this to back from the future advanced radiation from our future de Sitter horizon, we get exactly the observed dark energy density hc/Lp^2A

      However, let's look at retarded radiation from black holes in our past light cone.


      a solar mass black hole is ~ 3km ~ 10^5 cm

      Lprs ~ 10^-33x10^5 ~ 10^-28 cm^2

      The geometric mean wavelength is ~ 10^-14 cm

      i.e. signal frequency ~ 10^24 Hz

      What about a super-massive black hole?
      for 10^10 solar masses


      10^-33 x 10^15 ~ 10^-18 cm^2

      i.e. wavelength ~ 10^-9 cm

      signal frequency ~ 10^19 Hz GAMMA RAY

      see also http://en.wikipedia.org/wiki/Gamma-ray_burst

      However, this radiation should not be usually in burst form, but should be a steady signal.

      For the universe as a whole, i.e. our future cosmic event horizon in the causal diamond

      Lprs ~ 10^-33 x 10^29 ~ 10^-4 cm^2

      i.e. advanced Wheeler-Feynman dark energy peak signal frequency ~ 10^14 Hz.

      visible light is 10^15 Hz
      The Schwarzschild radius (sometimes historically referred to as the gravitational radius) is the radius of a sphere such that, if all the mass of an object is compressed within that sphere, the escape speed from the surface of the sphere would equal the speed of light. An example of an object smalle...